Optimal. Leaf size=281 \[ -\frac{2 e^4 \sqrt{\sin (2 c+2 d x)} \sec (c+d x) \text{EllipticF}\left (c+d x-\frac{\pi }{4},2\right )}{a^2 d \sqrt{e \tan (c+d x)}}-\frac{e^{7/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}\right )}{\sqrt{2} a^2 d}+\frac{e^{7/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}+1\right )}{\sqrt{2} a^2 d}+\frac{2 e^3 \sqrt{e \tan (c+d x)}}{a^2 d}-\frac{e^{7/2} \log \left (\sqrt{e} \tan (c+d x)-\sqrt{2} \sqrt{e \tan (c+d x)}+\sqrt{e}\right )}{2 \sqrt{2} a^2 d}+\frac{e^{7/2} \log \left (\sqrt{e} \tan (c+d x)+\sqrt{2} \sqrt{e \tan (c+d x)}+\sqrt{e}\right )}{2 \sqrt{2} a^2 d} \]
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Rubi [A] time = 0.378175, antiderivative size = 281, normalized size of antiderivative = 1., number of steps used = 19, number of rules used = 15, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.6, Rules used = {3888, 3886, 3476, 329, 211, 1165, 628, 1162, 617, 204, 2614, 2573, 2641, 2607, 32} \[ -\frac{e^{7/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}\right )}{\sqrt{2} a^2 d}+\frac{e^{7/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}+1\right )}{\sqrt{2} a^2 d}+\frac{2 e^3 \sqrt{e \tan (c+d x)}}{a^2 d}-\frac{e^{7/2} \log \left (\sqrt{e} \tan (c+d x)-\sqrt{2} \sqrt{e \tan (c+d x)}+\sqrt{e}\right )}{2 \sqrt{2} a^2 d}+\frac{e^{7/2} \log \left (\sqrt{e} \tan (c+d x)+\sqrt{2} \sqrt{e \tan (c+d x)}+\sqrt{e}\right )}{2 \sqrt{2} a^2 d}-\frac{2 e^4 \sqrt{\sin (2 c+2 d x)} \sec (c+d x) F\left (\left .c+d x-\frac{\pi }{4}\right |2\right )}{a^2 d \sqrt{e \tan (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 3888
Rule 3886
Rule 3476
Rule 329
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rule 2614
Rule 2573
Rule 2641
Rule 2607
Rule 32
Rubi steps
\begin{align*} \int \frac{(e \tan (c+d x))^{7/2}}{(a+a \sec (c+d x))^2} \, dx &=\frac{e^4 \int \frac{(-a+a \sec (c+d x))^2}{\sqrt{e \tan (c+d x)}} \, dx}{a^4}\\ &=\frac{e^4 \int \left (\frac{a^2}{\sqrt{e \tan (c+d x)}}-\frac{2 a^2 \sec (c+d x)}{\sqrt{e \tan (c+d x)}}+\frac{a^2 \sec ^2(c+d x)}{\sqrt{e \tan (c+d x)}}\right ) \, dx}{a^4}\\ &=\frac{e^4 \int \frac{1}{\sqrt{e \tan (c+d x)}} \, dx}{a^2}+\frac{e^4 \int \frac{\sec ^2(c+d x)}{\sqrt{e \tan (c+d x)}} \, dx}{a^2}-\frac{\left (2 e^4\right ) \int \frac{\sec (c+d x)}{\sqrt{e \tan (c+d x)}} \, dx}{a^2}\\ &=\frac{e^4 \operatorname{Subst}\left (\int \frac{1}{\sqrt{e x}} \, dx,x,\tan (c+d x)\right )}{a^2 d}+\frac{e^5 \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \left (e^2+x^2\right )} \, dx,x,e \tan (c+d x)\right )}{a^2 d}-\frac{\left (2 e^4 \sqrt{\sin (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \sqrt{\sin (c+d x)}} \, dx}{a^2 \sqrt{\cos (c+d x)} \sqrt{e \tan (c+d x)}}\\ &=\frac{2 e^3 \sqrt{e \tan (c+d x)}}{a^2 d}+\frac{\left (2 e^5\right ) \operatorname{Subst}\left (\int \frac{1}{e^2+x^4} \, dx,x,\sqrt{e \tan (c+d x)}\right )}{a^2 d}-\frac{\left (2 e^4 \sec (c+d x) \sqrt{\sin (2 c+2 d x)}\right ) \int \frac{1}{\sqrt{\sin (2 c+2 d x)}} \, dx}{a^2 \sqrt{e \tan (c+d x)}}\\ &=-\frac{2 e^4 F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sec (c+d x) \sqrt{\sin (2 c+2 d x)}}{a^2 d \sqrt{e \tan (c+d x)}}+\frac{2 e^3 \sqrt{e \tan (c+d x)}}{a^2 d}+\frac{e^4 \operatorname{Subst}\left (\int \frac{e-x^2}{e^2+x^4} \, dx,x,\sqrt{e \tan (c+d x)}\right )}{a^2 d}+\frac{e^4 \operatorname{Subst}\left (\int \frac{e+x^2}{e^2+x^4} \, dx,x,\sqrt{e \tan (c+d x)}\right )}{a^2 d}\\ &=-\frac{2 e^4 F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sec (c+d x) \sqrt{\sin (2 c+2 d x)}}{a^2 d \sqrt{e \tan (c+d x)}}+\frac{2 e^3 \sqrt{e \tan (c+d x)}}{a^2 d}-\frac{e^{7/2} \operatorname{Subst}\left (\int \frac{\sqrt{2} \sqrt{e}+2 x}{-e-\sqrt{2} \sqrt{e} x-x^2} \, dx,x,\sqrt{e \tan (c+d x)}\right )}{2 \sqrt{2} a^2 d}-\frac{e^{7/2} \operatorname{Subst}\left (\int \frac{\sqrt{2} \sqrt{e}-2 x}{-e+\sqrt{2} \sqrt{e} x-x^2} \, dx,x,\sqrt{e \tan (c+d x)}\right )}{2 \sqrt{2} a^2 d}+\frac{e^4 \operatorname{Subst}\left (\int \frac{1}{e-\sqrt{2} \sqrt{e} x+x^2} \, dx,x,\sqrt{e \tan (c+d x)}\right )}{2 a^2 d}+\frac{e^4 \operatorname{Subst}\left (\int \frac{1}{e+\sqrt{2} \sqrt{e} x+x^2} \, dx,x,\sqrt{e \tan (c+d x)}\right )}{2 a^2 d}\\ &=-\frac{e^{7/2} \log \left (\sqrt{e}+\sqrt{e} \tan (c+d x)-\sqrt{2} \sqrt{e \tan (c+d x)}\right )}{2 \sqrt{2} a^2 d}+\frac{e^{7/2} \log \left (\sqrt{e}+\sqrt{e} \tan (c+d x)+\sqrt{2} \sqrt{e \tan (c+d x)}\right )}{2 \sqrt{2} a^2 d}-\frac{2 e^4 F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sec (c+d x) \sqrt{\sin (2 c+2 d x)}}{a^2 d \sqrt{e \tan (c+d x)}}+\frac{2 e^3 \sqrt{e \tan (c+d x)}}{a^2 d}+\frac{e^{7/2} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}\right )}{\sqrt{2} a^2 d}-\frac{e^{7/2} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}\right )}{\sqrt{2} a^2 d}\\ &=-\frac{e^{7/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}\right )}{\sqrt{2} a^2 d}+\frac{e^{7/2} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt{e \tan (c+d x)}}{\sqrt{e}}\right )}{\sqrt{2} a^2 d}-\frac{e^{7/2} \log \left (\sqrt{e}+\sqrt{e} \tan (c+d x)-\sqrt{2} \sqrt{e \tan (c+d x)}\right )}{2 \sqrt{2} a^2 d}+\frac{e^{7/2} \log \left (\sqrt{e}+\sqrt{e} \tan (c+d x)+\sqrt{2} \sqrt{e \tan (c+d x)}\right )}{2 \sqrt{2} a^2 d}-\frac{2 e^4 F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sec (c+d x) \sqrt{\sin (2 c+2 d x)}}{a^2 d \sqrt{e \tan (c+d x)}}+\frac{2 e^3 \sqrt{e \tan (c+d x)}}{a^2 d}\\ \end{align*}
Mathematica [F] time = 3.87051, size = 0, normalized size = 0. \[ \int \frac{(e \tan (c+d x))^{7/2}}{(a+a \sec (c+d x))^2} \, dx \]
Verification is Not applicable to the result.
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Maple [C] time = 0.259, size = 653, normalized size = 2.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \tan \left (d x + c\right )\right )^{\frac{7}{2}}}{{\left (a \sec \left (d x + c\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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